Get The Radio Button Value Through Ajax To Php File
After clicking the radio button, the value from the radio button is not being passed when the onclick event is triggered. Here is my code:
Solution 2:
<input type="radio" id="status" name="status" value="1" /> Mbyllur<br />
<input type="radio" id="status" name="status" value="0" /> Hapur<br />
function MyAlert()
{
var radio1=$('input[type="radio"]:checked').val();
var pass_data = {
'radio1' : $('input[name=status]:checked').val(),
};
alert(pass_data);
$.ajax({
url : "",
type : "POST",
data : pass_data,
success : function(data) {
}
});
return false;
}
Solution 3:
I would use a newer version of jquery .
You can't give two elements the same id.
I would rewrite the code as follow :
$(function() {
$(document).on('change', '[name="radio1"]' , function(){
var val = $('[name="radio1"]:checked').val();
alert(val);
/*
Ajax code 1 (GET) :
$.get('/myurl?val=' + val, function(){
});
Ajax code 2 (POST) :
$.post('/myurl', {val : val}, function(){
});
*/
});
});
<form name="Form1" id="color" style="font-size: 100%" action="#" >
<input type="radio" name="radio1" value="blue"/>Blue <br />
<p> <input type="radio" name="radio1" value="red"/>Red
</form>
<script src="https://code.jquery.com/jquery-1.12.3.min.js"></script>
Solution 4:
Try This -->
<form name="Form1" id="color" style="font-size: 100%" action="#" >
<input type="radio" name="radio1" id="radio1" onclick = "MyAlert()" value="blue"/>Blue <br /></p>
<p> <input type="radio" name="radio1" id="radio1" onclick = "MyAlert()" value="red"/>Red
</form>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
function MyAlert()
{
var radio1=$('input[type="radio"]:checked').val();
//alert(radio1);
var pass_data = {
'radio1' : radio1,
};
//alert(pass_data);
$.ajax({
url : "request.php", // create a new php page to handle ajax request
type : "POST",
data : pass_data,
success : function(data) {
}
});
return false;
}
</script>
request.php
<?php
if(isset($_POST['radio1']))
{
echo $radio1=$_POST['radio1'];
}
?>
Above code handle with ajax so, its not refresh the page.
Solution 5:
<script>
$(document).ready(function() {
$("#Enviar").click(function (e) {
var cedula = document.getElementById("Cedula").value;
var Nombre = document.getElementById("Nombre").value;
var Apellido = document.getElementById("Apellido").value;
var Sexo = $('input:radio[name=SexoC]:checked').val();
var Edad = document.getElementById("Edad").value;
var FechaN = document.getElementById("date").value;
var Tele = document.getElementById("tel").value;
var Direccion = document.getElementById("Direccion").value;
var Invitacion = document.getElementById("Invitacion").value;
var CasaG = document.getElementById("CasaG").value;
var Rango = document.getElementById("Rango").value;
var cadena = "Cedula="+cedula+"&Nombre="+Nombre+"&Apellido="+Apellido+"&Sexo="+Sexo+"&Edad="+Edad+"&Fecha="+FechaN+"&Tele="+Tele+"&Direccion="+Direccion+"&Invitacion="+Invitacion+"&CasaG="+CasaG+"&Rango="+Rango;
$.ajax({
type:'POST',
url:'datos/Registrar.php',
data: cadena,
beforeSend: function(){
console.log(cadena);
},
success:function(Resp){
alert(Resp);
}
});
return false;
});
});
</script>
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