Regex Shortest Possible Match

Given: A 1234 AAAAAA AAAAAA 1234 7th XXXXX Rd XXXXXX I want to match: 1234 7th XXXXX Rd Using nothing more than Rd and \d+ so i tried: \d+.*?Rd but it matches starting from the

Solution 1:

You are using more than Rd and \d+ when you add .* which will match anything. If you can assume NUMBER-SPACE-SOMETHING-Rd as the format - then you could add \s to the mix and use

/(\d+\s+\d+.*?Rd)/

console.log('A 1234 AAAAAA AAAAAA 1234 7th XXXXX Rd XXXXXX'.match(/(\d+\s+\d+.*?Rd)/g))

Solution 2:

Use the following pattern:

^.*(1234 7th.*?Rd).*$

Explanation:

^.*from the startof the greedily consume everything until
(12347th  capture from the last occurrence of12347th
.*?Rd)     then non greedily consume everything until the first Rd
.*$        consume, but don't capture, the remainder of the string

Here is a code snippet:

var input = "A 1234 AAAAAA AAAAAA 1234 7th XXXXX Rd XXXXXX";
var regex = /^.*(1234 7th.*?Rd).*$/g;
var match = regex.exec(input);
console.log(match[1]); // 1234 7th XXXXX Rd