How Do I Iterate Over The Results Of A Jquery Selector? January 28, 2024 Post a Comment When I'm trying to store all elements as objects in array (using $('a')), and then get the position of each of them, it doesn't work. years = $('a'); for(i=0;i< yearsSolution 1: Use this instead:$("a").each(function() { var pos = $(this).position(); if (pos.top > year.position().top) { // hurray } }); CopyAlso what is the value of year? I prefer to name jQuery objects like this: var $year = $("#year"); The $ helps you remember it's a jQuery object. Solution 2: You can do the following:Baca JugaAjax Posting Is Shown As Red Color In Firebug ConsoleEmbed Facebook Albums Into WebsiteFocus Textarea With Caret After Text In Android Browservar arr = [], elems = $('a'); for(var i = 0; i < elems.length; i++){ arr[i] = elems[i]; } Copy Share You may like these postsSort By Image Resolution In GalleryDatatables Jquery Click Event Not Working After PaginationAftershow Event On Jquery DatepickerImproving Website Performance By Dynamically Loading Javascript? Post a Comment for "How Do I Iterate Over The Results Of A Jquery Selector?"
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