How To Download In Bash From Zippyshare?

Can anyone help me how to download files from zippyshare.com using bash (server with CentOS)? Their download button made with flash, so i can't retrieve download link.

Solution 1:

It's definitely possible, but it's a little hacky. I've been doing it myself for quite some time using wget. The trick is to make the server think that the request is being made from a browser and to make that happen, you need a couple of things:

• The Download Link (The actual link to the file)
• Link Referrer (The webpage with the download button)
• Zippyshare Session ID (Found in Cookies)

Here's a screenshot explaining where you can get each item:

Now open up your terminal, and use the following command (replacing necessary items):

wget <download_link> \
--referer='<referrer>' \
--cookies=off --header "Cookie: JSESSIONID=<session_id>" \
--user-agent='Mozilla/5.0 (Windows NT 6.0) Gecko/20100101 Firefox/14.0.1'

Example:

wget http://www16.zippyshare.com/d/29887835/8895183/hello.txt \
--referer='http://www16.zippyshare.com/v/29887835/file.html' \
--cookies=off --header "Cookie: JSESSIONID=26458C0893BF69F88EB5743D74FE0F8C" \
--user-agent='Mozilla/5.0 (Windows NT 6.0) Gecko/20100101 Firefox/14.0.1'

Original answer: How to use wget to download from hosting sites?

Note: In the command, it is in fact 'referer' not 'referrer'

Solution 2:

Use Web developer tools from browser (IE/Chrome come with build-in, for Firefox use Firebug). Under network traffic tab look what HTTP request performed to download file.

Next step is to use wget or curl utility.

Reversing step is your task, make something by own...

Solution 3:

Why don't you give a try to PlowShare it can be found here

https://code.google.com/p/plowshare/

Example to download

plowdown http://www3.zippyshare.com/v/92458242/file.html

hope this helps. For more help https://code.google.com/p/plowshare/wiki/Readme4